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Consider a metal used to produced some c...

Consider a metal used to produced some characteristic X-ray, energy of X-ray are given by `E` and wavelength as represented by `lambda`. Then which of the following is true:

A

`E(K_(alpha)) gt E(K_(beta)) gt E(K_(gamma))`

B

`E(M_(alpha)) gt E(L_(alpha)) gt E(K_(alpha))`

C

`lambda(K_(alpha)) gt lambda(K_(beta)) gt lambda(K_(gamma))`

D

`lambda(M_(alpha)) gt lambda(L_(alpha)) gt lamda(K_(alpha))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the characteristic X-ray energies and wavelengths, we will follow these steps: ### Step 1: Understand the Concept of Characteristic X-rays Characteristic X-rays are emitted when electrons transition between energy levels in an atom. The energy of the emitted X-ray is equal to the difference in energy between the two levels involved in the transition. ### Step 2: Use the Energy-Wavelength Relationship The energy (E) of a photon is related to its wavelength (λ) by the equation: \[ E = \frac{hc}{\lambda} \] where \(h\) is Planck's constant and \(c\) is the speed of light. This implies that energy is inversely proportional to wavelength. ### Step 3: Identify the Energy Levels For the K, L, and M shells, the energy levels can be calculated using the formula: \[ E_n = -\frac{13.6 \text{ eV}}{n^2} \] where \(n\) is the principal quantum number (1 for K, 2 for L, and 3 for M). ### Step 4: Calculate the Energy Differences for K-series 1. For Kα (transition from L to K): - \(E_{K} = -13.6 \text{ eV}\) (n=1) - \(E_{L} = -3.4 \text{ eV}\) (n=2) - Energy of Kα = \(E_{K} - E_{L} = -13.6 + 3.4 = 10.2 \text{ eV}\) 2. For Kβ (transition from M to K): - \(E_{M} = -1.51 \text{ eV}\) (n=3) - Energy of Kβ = \(E_{K} - E_{M} = -13.6 + 1.51 = 12.09 \text{ eV}\) 3. For Kγ (transition from N to K): - \(E_{N} = -0.85 \text{ eV}\) (n=4) - Energy of Kγ = \(E_{K} - E_{N} = -13.6 + 0.85 = 12.75 \text{ eV}\) ### Step 5: Compare Energies From the calculations: - \(E_{Kα} = 10.2 \text{ eV}\) - \(E_{Kβ} = 12.09 \text{ eV}\) - \(E_{Kγ} = 12.75 \text{ eV}\) Thus, the order of energy is: \[ E_{Kα} < E_{Kβ} < E_{Kγ} \] ### Step 6: Analyze the Options Given the relationships derived, we can analyze the options provided in the question. If an option states that \(E_{Kα} > E_{Kβ} > E_{Kγ}\), it is incorrect. The correct relationships should reflect the order derived from the calculations. ### Conclusion Based on the analysis, the correct statements regarding the energies and wavelengths of the X-rays can be determined from the calculations.

To solve the problem regarding the characteristic X-ray energies and wavelengths, we will follow these steps: ### Step 1: Understand the Concept of Characteristic X-rays Characteristic X-rays are emitted when electrons transition between energy levels in an atom. The energy of the emitted X-ray is equal to the difference in energy between the two levels involved in the transition. ### Step 2: Use the Energy-Wavelength Relationship The energy (E) of a photon is related to its wavelength (λ) by the equation: \[ ...
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