An `alpha` particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are `lambda_a`
and `lambda_p` respectively. The ratio `(lambda_p)/(lambda_a)`, to the nearest integer, is.

Answer

`3`

Explanation

`P_(1) = sqrt(2m(100 eV))`
`lambda_(P) = (h)/(sqrt(2m(100eV))) rArr lambda_(alpha)=(h)/(sqrt(2(4m)2(100 eV)))`
`lambda_(P)/lambda_(alpha)=sqrt(8)`
rArr The ratio `lambda_(p)/lambda_(alpha)`, to the nearest integer, is equal to `3`.