Home
Class 12
PHYSICS
A dence collection of equal number of el...

A dence collection of equal number of electrona and positive ions is called netural plasma. Certain solids contianing fixed positive ions surroundedby free electrons can be treated as neytral plasma. Let 'N' be the numbrer density of free electrons, each of mass '`m`'. When the elctrons are subjected to an eletric field, they are displaced relatively away from the heavy positive ions. if the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency '`omega_(P)'` which is called the plasma frequency. to sustain the oscillations, a time varying electric field needs to be applied that has an angular frequrncy `omega`, where a part of the energy is absorbed and a part of it is reflected. As `omega` approaches `omega_(p)` all the free electrons are set to resonance together and all the energy is reflected. this is the explaination of high reflectivity of metals.
(1) Taking the electronic charge as 'e' and the permittivity as `'epsilon_(0)`'. use dimensional analysis to determine the correct expression for `omega_(p)`.

A

`sqrt((Ne)/(mepsilon_(0)))`

B

`sqrt((mepsilon_(0))/(Ne))`

C

`sqrt((Ne^(2))/(mepsilon_(0)))`

D

`sqrt((mepsilon_(0))/(Ne^(2)))`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the plasma frequency \( \omega_p \) using dimensional analysis, we need to consider the relevant quantities: the charge of the electron \( e \), the permittivity of free space \( \epsilon_0 \), and the number density of free electrons \( N \) (which has dimensions of \( L^{-3} \)). The mass of the electron \( m \) is also relevant. ### Step-by-step Solution: 1. **Identify the Dimensions of Each Quantity**: - Charge \( e \): The dimension of charge can be expressed in terms of current (ampere) and time. Thus, the dimension of charge is \( [e] = [I][T] = [A][T] \). - Permittivity \( \epsilon_0 \): The dimension of permittivity can be derived from Coulomb's law. It is given as \( [\epsilon_0] = [M^{-1} L^{-3} T^4 A^2] \). - Number density \( N \): This is the number of particles per unit volume, so its dimension is \( [N] = [L^{-3}] \). - Mass \( m \): The dimension of mass is simply \( [M] \). - Angular frequency \( \omega \): The dimension of angular frequency is \( [\omega] = [T^{-1}] \). 2. **Construct a Dimensional Formula for \( \omega_p \)**: We want to find a combination of \( e \), \( \epsilon_0 \), \( N \), and \( m \) that results in the dimension of \( [T^{-1}] \). Let’s assume: \[ \omega_p \propto \sqrt{\frac{N e^2}{m \epsilon_0}} \] 3. **Determine the Dimensions of the Right Side**: - The dimension of \( N e^2 \): \[ [N e^2] = [L^{-3}] \cdot [A^2 T^2] = [L^{-3} A^2 T^2] \] - The dimension of \( m \epsilon_0 \): \[ [m \epsilon_0] = [M] \cdot [M^{-1} L^{-3} T^4 A^2] = [L^{-3} T^4 A^2] \] 4. **Combine the Dimensions**: \[ \frac{N e^2}{m \epsilon_0} = \frac{[L^{-3} A^2 T^2]}{[L^{-3} T^4 A^2]} = [T^{-2}] \] 5. **Take the Square Root**: \[ \sqrt{\frac{N e^2}{m \epsilon_0}} = [T^{-1}] \] 6. **Final Expression for Plasma Frequency**: Thus, the plasma frequency \( \omega_p \) can be expressed as: \[ \omega_p = \sqrt{\frac{N e^2}{m \epsilon_0}} \] ### Conclusion: The correct expression for the plasma frequency \( \omega_p \) is: \[ \omega_p = \sqrt{\frac{N e^2}{m \epsilon_0}} \]

To determine the plasma frequency \( \omega_p \) using dimensional analysis, we need to consider the relevant quantities: the charge of the electron \( e \), the permittivity of free space \( \epsilon_0 \), and the number density of free electrons \( N \) (which has dimensions of \( L^{-3} \)). The mass of the electron \( m \) is also relevant. ### Step-by-step Solution: 1. **Identify the Dimensions of Each Quantity**: - Charge \( e \): The dimension of charge can be expressed in terms of current (ampere) and time. Thus, the dimension of charge is \( [e] = [I][T] = [A][T] \). - Permittivity \( \epsilon_0 \): The dimension of permittivity can be derived from Coulomb's law. It is given as \( [\epsilon_0] = [M^{-1} L^{-3} T^4 A^2] \). - Number density \( N \): This is the number of particles per unit volume, so its dimension is \( [N] = [L^{-3}] \). ...
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos
  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Exercise-2 Part-III : Comprehension|12 Videos
  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise HIGH LEVEL PROBLEMS|11 Videos
  • CAPACITANCE

    RESONANCE ENGLISH|Exercise High Level Problems|16 Videos

Similar Questions

Explore conceptually related problems

A dence collection of equal number of electrona and positive ions is called netural plasma. Certain solids contianing fixed positive ions surroundedby free electrons can be treated as neytral plasma. Let 'N' be the numbrer density of free electrons, each of mass ' m '. When the elctrons are subjected to an eletric field, they are displaced relatively away from the heavy positive ions. if the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency ' omega_(P)' which is called the plasma frequency. to sustain the oscillations, a time varying electric field needs to be applied that has an angular frequrncy omega , where a part of the energy is absorbed and a part of it is reflected. As omega approaches omega_(p) all the free electrons are set to resonance together and all the energy is reflected. this is the explaination of high reflectivity of metals. (2) Estimate the wavelength at which plasma reflection will occur for a metal having the density of electrons N~~ 4 xx 10^(27)m^(-3) . Taking epsilon_(0) = 10^(11) and mass m~~ 10^(-30) , where these quantities are in proper SI units.

Give reason : Metals form positive ions.

An atom that loses one or more electrons to form a positive ion is called a ____

The position of the point where the net electric field will be zero is

The loss of positive ions from the interior of a neuron produces

Number of valence electrons in Cl^(– ) ion are:

Number of valence electrons in Cl^(– ) ion are:

The total number of valence electrons in 4. 2g of N_3^- ion are :

An atom that loses electrons becomes a positively-charged ion called

A dispositive ion 16 protons what is the number of electron is its tetrapositive ion?

RESONANCE ENGLISH-ATOMIC PHYSICS-Exercise -3 part -I JEE (Advanced)
  1. The key feature of Bohr's theory of spectrum of hydrogen atom is the q...

    Text Solution

    |

  2. if the wavelength of the first line of the balmer series of hydrogen i...

    Text Solution

    |

  3. A dence collection of equal number of electrona and positive ions is ...

    Text Solution

    |

  4. A dence collection of equal number of electrona and positive ions is ...

    Text Solution

    |

  5. A silver sphere of radius 1 cm and work function 4.7 eV is suspended f...

    Text Solution

    |

  6. A pulse of light of duration 100 ns is absorbed completely by a small ...

    Text Solution

    |

  7. The work function of Silver and sodium are 4.6 and 2.3 eV, respective...

    Text Solution

    |

  8. The radius of the orbit of an electron in Hydrogen-like aton is 4.5 al...

    Text Solution

    |

  9. if lambda(Cu) is the wavelength of Kalpha, X-ray line fo copper (atomi...

    Text Solution

    |

  10. A metal surface is illuminated by light of two different wavelengths 2...

    Text Solution

    |

  11. Consider a hydrogen atom with its electron in the n^(th) orbital An el...

    Text Solution

    |

  12. For photo - electric effect with incident photon wavelength lambda the...

    Text Solution

    |

  13. An electron is an excited state of Li^(2 + )ion has angular momentum 3...

    Text Solution

    |

  14. The intensity of gamma radiation from a given source is I. on passing ...

    Text Solution

    |

  15. A photo cell is illuminated by a small bright source placed 1m away Wh...

    Text Solution

    |

  16. The diagram shows the energy levels for an electron in a certain atom....

    Text Solution

    |

  17. If the kinetic energy of a free electron doubles . Find the factor by ...

    Text Solution

    |

  18. The time taken by a photoelectron to come out after the photon strikes...

    Text Solution

    |

  19. An alpha nucleus of energy (1)/(2)mv^(2) bomobards a heavy nuclear tar...

    Text Solution

    |

  20. The threshold frequency for a metallic surface corresponds to an energ...

    Text Solution

    |