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An alpha nucleus of energy (1)/(2)mv^(2)...

An alpha nucleus of energy `(1)/(2)mv^(2)` bomobards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to

A

`(1)/(Ze)`

B

`v^(2)`

C

`(1)/(m)`

D

`(1)/(v^(4))`

Text Solution

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The correct Answer is:
C
`(1)/(m)`
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RESONANCE ENGLISH-ATOMIC PHYSICS-Exercise -3 part -I JEE (Advanced)
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