De Broglie wavelength associated with an electron acclerated through a potential difference `V` is `lambda`. What will be its wavelength when the accelerating potential is increased to `4 V`?

Explanation

To solve the problem, we need to understand the relationship between the de Broglie wavelength of an electron and the potential difference through which it is accelerated.

### Step-by-step Solution:

1. **Understanding De Broglie Wavelength**:
The de Broglie wavelength (λ) of a particle is given by the formula:
\[
\lambda = \frac{h}{p}
...