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The stopping potential in an experiment on photoelectric effect is 1.5 V. What is the maximum kinetic energy of the photoelectrons emitted ?

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The maximum kinetic energy of an electron is given by
`K_(max)=eV " "[ because V_(0)=1.5V]`
`=1.6xx10^(-19)xx1.5=2.4xx10^(-19)J`.
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RESONANCE ENGLISH-ATOMIC PHYSICS-Exercise -3 part -I JEE (Advanced)
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