The ground state energy of hydrogen atom is `-13.6 eV` . What is the kinetic and potential energies of the electron in this state?

Explanation

Total energy `=(1)/(2)mv^(2)+((-Kze^(2))/(r )) " "( because (mv^(2))/(r )=(Kze^(2))/(r^(2)))`
`=(Kze^(2))/(2 r)`
`= -13.6 eV` (for `n=1, z=1`)
Kinetic energy `=(1)/(2) mv^(2)=(Kze^(2))/(2r)=13.6eV`
Potential energy `=(-Kze^(2))/(r )=2xx13.6= -27.2 eV`