What is the product obtained when glycine hydrochloride reacts with two equivalents of `NaOH` ? Write the chemical reactions involved.

Explanation

To determine the product obtained when glycine hydrochloride reacts with two equivalents of NaOH, we will follow these steps:

### Step 1: Identify the structure of glycine hydrochloride
Glycine (NH2CH2COOH) is an amino acid that exists in its zwitterionic form when in solution. When glycine reacts with hydrochloric acid (HCl), it forms glycine hydrochloride, which can be represented as:

\[ \text{NH}_3^+ \text{CH}_2 \text{COO}^- \text{Cl}^- \]

### Step 2: Reaction with the first equivalent of NaOH
When glycine hydrochloride reacts with the first equivalent of sodium hydroxide (NaOH), the following occurs:
- NaOH dissociates into Na⁺ and OH⁻ ions.
- The Na⁺ ion will combine with Cl⁻ to form NaCl.
- The OH⁻ ion will react with the H⁺ from the ammonium group (NH₃⁺) to form NH₂ (the amino group).

The reaction can be written as:

\[ \text{NH}_3^+ \text{CH}_2 \text{COO}^- \text{Cl}^- + \text{NaOH} \rightarrow \text{NH}_2 \text{CH}_2 \text{COO}^- \text{Na}^+ + \text{NaCl} + \text{H}_2\text{O} \]

### Step 3: Reaction with the second equivalent of NaOH
Now, we treat the product from the first reaction (sodium glycinate) with another equivalent of NaOH. The reaction proceeds as follows:
- The Na⁺ ion will remain associated with the COO⁻ group.
- The second OH⁻ ion will abstract a proton (H⁺) from the carboxylic acid group (COOH) of the sodium glycinate.

The reaction can be represented as:

\[ \text{NH}_2 \text{CH}_2 \text{COO}^- \text{Na}^+ + \text{NaOH} \rightarrow \text{NH}_2 \text{CH}_2 \text{COO}^- \text{Na}^+ + \text{H}_2\text{O} \]

### Final Product
After both reactions, the final product is sodium glycinate (sodium salt of glycine):

\[ \text{NH}_2 \text{CH}_2 \text{COO}^- \text{Na}^+ \]

### Summary of Reactions
1. Glycine hydrochloride reacts with NaOH to form sodium glycinate and NaCl.
2. Sodium glycinate remains stable in the presence of the second equivalent of NaOH, resulting in the same sodium glycinate.

### Final Answer
The product obtained when glycine hydrochloride reacts with two equivalents of NaOH is sodium glycinate (NH₂CH₂COO⁻Na⁺).

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