Sucrose on hydrolysis yields a mixture which is.

Options

A. optically inactive
B. dextrorotatory
C. laevorotatory
D. racemic

Explanation

To solve the question "Sucrose on hydrolysis yields a mixture which is," we can follow these steps:

### Step 1: Understand the Hydrolysis of Sucrose
- Sucrose (C12H22O11) is a disaccharide composed of glucose and fructose.
- When sucrose undergoes hydrolysis, it reacts with water (H2O) in the presence of an acid (like HCl) to break down into its constituent monosaccharides.

### Step 2: Write the Hydrolysis Reaction
- The reaction can be represented as:
\[ \text{C}_{12}\text{H}_{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{HCl}} \text{C}_6\text{H}_{12}\text{O}_6 + \text{C}_6\text{H}_{12}\text{O}_6 \]
- This results in the formation of D-glucose and D-fructose.

### Step 3: Analyze the Optical Activity
- D-glucose is dextrorotatory (rotates plane-polarized light to the right) with a specific rotation of +52.5°.
- D-fructose is levorotatory (rotates plane-polarized light to the left) with a specific rotation of -92.4°.

### Step 4: Determine the Resulting Mixture's Optical Activity
- Since the hydrolysis of sucrose produces an equimolar mixture of D-glucose and D-fructose, we need to consider their specific rotations.
- The total specific rotation of the mixture can be calculated by considering the contributions from both sugars:
- D-glucose contributes +52.5°.
- D-fructose contributes -92.4°.

### Step 5: Compare the Contributions
- Since the absolute value of the specific rotation of fructose (-92.4°) is greater than that of glucose (+52.5°), the resulting mixture will be levorotatory.
- Therefore, the mixture will exhibit a net levorotatory rotation.

### Conclusion
- The hydrolysis of sucrose yields a mixture that is levorotatory.

### Final Answer
- The correct answer is that sucrose on hydrolysis yields a mixture which is **levorotatory**.

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