In Ketohexose the possible optical isomers are

Options

A. 12
B. 4
C. 16
D. 8

Explanation

To determine the number of possible optical isomers in a ketohexose, we can follow these steps:

### Step 1: Understand the Structure of Ketohexose
Ketohexose is a type of sugar that contains six carbon atoms and a ketone functional group. The general structure can be represented as:
- CH2OH - C(=O) - CH(OH) - CH(OH) - CH(OH) - CH2OH

### Step 2: Identify the Chiral Centers
A chiral center (or stereocenter) is a carbon atom that is bonded to four different groups. In the case of ketohexose, we need to identify these chiral centers:
- In the structure of ketohexose, there are three chiral centers. These are typically found in the carbon atoms that are bonded to hydroxyl (–OH) groups and are not part of the carbonyl (C=O) group.

### Step 3: Calculate the Number of Optical Isomers
The number of optical isomers can be calculated using the formula:
\[ \text{Number of optical isomers} = 2^n \]
where \( n \) is the number of chiral centers.

In this case, since we have identified 3 chiral centers:
\[ n = 3 \]
Thus, the number of optical isomers is:
\[ 2^3 = 8 \]

### Step 4: Conclusion
Therefore, the possible optical isomers of ketohexose are 8.

### Final Answer
The correct answer is 8 optical isomers.

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