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4 L of gas is enclosed in a vessel at a ...

4 L of gas is enclosed in a vessel at a pressure of 760 mm Hg. If temperature remain constant , calculate pressure when volume changes to 5L

A

380 mm Hg

B

608 mm Hg

C

840 mm Hg

D

420 mm Hg

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The correct Answer is:
To solve the problem, we will use Boyle's Law, which states that for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. The formula for Boyle's Law can be expressed as: \[ P_1 V_1 = P_2 V_2 \] Where: - \( P_1 \) = initial pressure - \( V_1 \) = initial volume - \( P_2 \) = final pressure - \( V_2 \) = final volume ### Step-by-Step Solution: 1. **Identify the given values:** - Initial pressure (\( P_1 \)) = 760 mm Hg - Initial volume (\( V_1 \)) = 4 L - Final volume (\( V_2 \)) = 5 L 2. **Set up the equation using Boyle's Law:** \[ P_1 V_1 = P_2 V_2 \] 3. **Rearrange the equation to solve for \( P_2 \):** \[ P_2 = \frac{P_1 V_1}{V_2} \] 4. **Substitute the known values into the equation:** \[ P_2 = \frac{760 \, \text{mm Hg} \times 4 \, \text{L}}{5 \, \text{L}} \] 5. **Calculate the value:** \[ P_2 = \frac{3040 \, \text{mm Hg}}{5} = 608 \, \text{mm Hg} \] 6. **Conclusion:** The final pressure (\( P_2 \)) when the volume changes to 5 L is 608 mm Hg. ### Final Answer: The pressure when the volume changes to 5 L is **608 mm Hg**.

To solve the problem, we will use Boyle's Law, which states that for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. The formula for Boyle's Law can be expressed as: \[ P_1 V_1 = P_2 V_2 \] Where: - \( P_1 \) = initial pressure - \( V_1 \) = initial volume - \( P_2 \) = final pressure ...
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