Home
Class 12
CHEMISTRY
D-Mannose differs from D-glucose in its ...

D-Mannose differs from D-glucose in its stereochemistry at `C-2`. The pyranose form of D-Mannose is.

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To determine the structure of the pyranose form of D-Mannose, we need to analyze its stereochemistry, particularly at C-2, and compare it with D-Glucose. Here’s a step-by-step solution: ### Step 1: Understand the Structure of D-Glucose - D-Glucose can exist in two anomeric forms: alpha (α) and beta (β). - In the pyranose form, D-Glucose has a six-membered ring structure with five carbon atoms and one oxygen atom. ### Step 2: Draw the Pyranose Form of D-Glucose - For α-D-Glucose, the hydroxyl group (OH) on the anomeric carbon (C-1) is positioned below the plane of the ring. - For β-D-Glucose, the hydroxyl group on C-1 is above the plane of the ring. ### Step 3: Identify the Difference at C-2 - D-Mannose differs from D-Glucose at C-2. In D-Glucose, the configuration at C-2 is (OH on the right), while in D-Mannose, it is (OH on the left). ### Step 4: Draw the Pyranose Form of D-Mannose - For α-D-Mannose, the structure will be similar to α-D-Glucose, but with the OH group on C-2 positioned to the left. - For β-D-Mannose, the structure will have the OH group on C-1 above the plane and the OH group on C-2 to the left. ### Step 5: Final Structures - The final structures for α-D-Mannose and β-D-Mannose can be summarized as follows: - **α-D-Mannose**: OH on C-1 is below the plane, and OH on C-2 is to the left. - **β-D-Mannose**: OH on C-1 is above the plane, and OH on C-2 is to the left. ### Conclusion The pyranose form of D-Mannose can be represented in both α and β forms, with the key difference in stereochemistry at C-2 compared to D-Glucose. ---
Promotional Banner

Topper's Solved these Questions

  • BIOMOLECULES

    RESONANCE ENGLISH|Exercise Ex-2(Comprehension)Part-IV|5 Videos
  • BIOMOLECULES

    RESONANCE ENGLISH|Exercise Ex-3(IIT-JEE)Part-I|18 Videos
  • BIOMOLECULES

    RESONANCE ENGLISH|Exercise Ex-2(Single correct)Part-II|17 Videos
  • BASIC CONCEPTS

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(BASIC CONCEPTS)|27 Videos
  • BIOMOLECULES & POLYMER

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Biomolecules & Polymer)|34 Videos

Similar Questions

Explore conceptually related problems

C_3 -epimer of D-Glucose is

The letter D in D-glucose signifies.

Polymer of alpha -D glucose is

D - Glucose and D - Mannose are :

The correct IUPAC name of D-Glucose is :

The anomeric carbon in D(+) glucose is

Correct statement for alpha -D-glucose is

D (+) Glucose has melting point 146^@ C and specific rotation [alpha]_(D)^(25) is + 112^@ C. Another D(+) Glucose has melting point 150^@ C and specific rotational [alpha]_(D)^(25) is + 18.7^@ C. The two form have significantly different optical rotation but when an aqueous solution of either form is allowed to stand, it rotation changes. The specific rotation of one form decreases and rotation of other increases until both solution show the same value +52.7^@ . The change in rotation towards an equilibrium value is called mutarotation. For mannose the mutarotation can be shown in brief as follow: