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Find rms speed of Lithium molecules at t...

Find rms speed of Lithium molecules at temperature `27^(@)C`..

A

100m/s

B

1034m/s

C

1000m/s

D

1459m/s

Text Solution

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The correct Answer is:
To find the root mean square (rms) speed of lithium molecules at a temperature of 27°C, we can follow these steps: ### Step 1: Convert Temperature to Kelvin The temperature given is 27°C. To convert this to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] Substituting the value: \[ T = 27 + 273 = 300 \, K \] ### Step 2: Identify the Molar Mass of Lithium The molar mass of lithium (Li) is approximately 7 g/mol. To use this in our calculations, we need to convert it to kilograms per mole: \[ M = 7 \, g/mol = 7 \times 10^{-3} \, kg/mol \] ### Step 3: Use the RMS Speed Formula The formula for calculating the rms speed (\(v_{rms}\)) is given by: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] where: - \(R\) is the gas constant, \(8.31 \, J/(K \cdot mol)\) - \(T\) is the temperature in Kelvin - \(M\) is the molar mass in kg/mol ### Step 4: Substitute Values into the Formula Now we substitute the values into the rms speed formula: \[ v_{rms} = \sqrt{\frac{3 \times 8.31 \, J/(K \cdot mol) \times 300 \, K}{7 \times 10^{-3} \, kg/mol}} \] ### Step 5: Calculate the Value Calculating the numerator: \[ 3 \times 8.31 \times 300 = 7479 \, J/mol \] Now, substituting this into the formula: \[ v_{rms} = \sqrt{\frac{7479}{7 \times 10^{-3}}} \] Calculating the denominator: \[ 7 \times 10^{-3} = 0.007 \, kg/mol \] Now we can calculate: \[ v_{rms} = \sqrt{1067000} \approx 1033.6 \, m/s \] ### Final Answer Thus, the rms speed of lithium molecules at 27°C is approximately: \[ v_{rms} \approx 1034 \, m/s \]

To find the root mean square (rms) speed of lithium molecules at a temperature of 27°C, we can follow these steps: ### Step 1: Convert Temperature to Kelvin The temperature given is 27°C. To convert this to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] Substituting the value: ...
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