Glucose on reduction with `Na//Hg` and water gives:

Options

A. Sorbitol
B. Fructose
C. Saccharic acid
D. Gluconic acid

Answer

To solve the question "Glucose on reduction with Na/Hg and water gives:", we will follow these steps:

### Step 1: Understand the Reactants
We start with glucose, which is a simple sugar with the molecular formula C6H12O6. The structure of glucose includes an aldehyde group (-CHO) and multiple hydroxyl groups (-OH).

### Step 2: Identify the Reducing Agent
The reducing agent given in the question is sodium amalgam (Na/Hg), which is a source of sodium ions (Na+) and provides a reducing environment. When sodium amalgam is used in the presence of water, it can reduce aldehydes and ketones.

### Step 3: Recognize the Reaction Type
The reaction we are considering is a reduction reaction. In this case, the aldehyde group in glucose will be reduced to a primary alcohol.

### Step 4: Write the Reaction
When glucose is reduced by sodium amalgam in the presence of water, the aldehyde group (-CHO) at one end of the glucose molecule is converted into a primary alcohol (-CH2OH). The overall structure of glucose will change as follows:
- The aldehyde group (-CHO) becomes a primary alcohol (-CH2OH).
- The other hydroxyl groups (-OH) remain unchanged.

### Step 5: Identify the Product
The product formed from the reduction of glucose is known as sorbitol (or glucitol). Sorbitol has the molecular formula C6H14O6, which indicates that all carbon atoms in glucose are retained, but the aldehyde group has been converted into an alcohol.

### Conclusion
Thus, the final answer to the question is that glucose on reduction with Na/Hg and water gives **sorbitol**.

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