The charing product formed when `C_(6) H_(12) O_(6)` is heated with cone, `H_(2)SO_(4)` is due to:

Options

A. Oxidation
B. Reduction
C. Dehydration
D. Dehydrogenation

Answer

To solve the question about the charing product formed when glucose (C₆H₁₂O₆) is heated with concentrated sulfuric acid (H₂SO₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactant in this case is glucose, which has the molecular formula C₆H₁₂O₆.

2. **Understand the Process:**
- When glucose is heated with concentrated sulfuric acid, it undergoes a chemical process known as charring. Charring is a form of incomplete combustion where organic material is heated, leading to the formation of carbon-rich residues.

3. **Chemical Reaction:**
- The concentrated sulfuric acid acts as a dehydrating agent. It removes water (H₂O) from glucose. The reaction can be summarized as:
\[ C_6H_{12}O_6 \xrightarrow{H_2SO_4} 6C + 6H_2O \]
- Here, 6 moles of water are removed from glucose, leaving behind pure carbon (charcoal).

4. **Identify the Products:**
- The products of this reaction are:
- Charcoal (pure carbon, represented as 6C)
- Water (6H₂O)

5. **Determine the Type of Reaction:**
- The removal of water indicates that this process is a dehydration reaction. It is not merely a dehydrogenation (removal of hydrogen) since oxygen is also being removed in the form of water.

6. **Conclusion:**
- The charing product formed when glucose is heated with concentrated sulfuric acid is primarily due to dehydration, resulting in the formation of charcoal and water.

### Final Answer:
The charing product formed when C₆H₁₂O₆ is heated with concentrated H₂SO₄ is due to dehydration, resulting in the formation of carbon (charcoal) and water.