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Number of electron in 1.8mL of H(2)O(l)...

Number of electron in `1.8mL` of `H_(2)O(l)`

A

`6.02xx10^(23)`

B

`3.011xx10^(23)`

C

`0.6022xx10^(23)`

D

`60.22xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
1
`d=1g//ml`
Mass `=Vxxd=1.8xx1=1.8g`
Number of electrons `=(1.8)/(18)xx10xxN_(a)=N_(a)`
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