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How many moles of KMnO(4) are needed to ...

How many moles of `KMnO_(4)` are needed to oxidise a mixture of 1 mole of each `FeSO_(4) & FeC_(2)O_(4)` in acidic medium `:`

A

`(4)/(5)`

B

`(5)/(4)`

C

`(3)/(4)`

D

`(5)/(3)`

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The correct Answer is:
To solve the problem of how many moles of `KMnO4` are needed to oxidize a mixture of 1 mole of `FeSO4` and 1 mole of `FeC2O4` in acidic medium, we can follow these steps: ### Step 1: Identify the oxidation states and changes - In `KMnO4`, manganese (Mn) is in the +7 oxidation state and gets reduced to +2 in acidic medium. - The change in oxidation state for Mn is: \[ +7 \text{ (Mn in KMnO4)} \rightarrow +2 \text{ (Mn}^{2+}\text{)} \] This is a change of 5 units. ### Step 2: Analyze the oxidation of `FeC2O4` - In `FeC2O4`, iron (Fe) is in the +2 oxidation state and gets oxidized to +3: \[ +2 \text{ (Fe}^{2+}\text{)} \rightarrow +3 \text{ (Fe}^{3+}\text{)} \] This is a change of 1 unit for Fe. - The oxalate ion (`C2O4^{2-}`) is oxidized to carbon dioxide (`CO2`), which involves the loss of 2 electrons: \[ C2O4^{2-} \rightarrow 2 \text{ CO2} + 2e^{-} \] Therefore, the total change in oxidation state for `FeC2O4` is: \[ 1 \text{ (for Fe)} + 2 \text{ (for C2O4)} = 3 \text{ units} \] ### Step 3: Analyze the oxidation of `FeSO4` - In `FeSO4`, iron (Fe) is also in the +2 oxidation state and gets oxidized to +3: \[ +2 \text{ (Fe}^{2+}\text{)} \rightarrow +3 \text{ (Fe}^{3+}\text{)} \] This is a change of 1 unit. ### Step 4: Calculate the total equivalents of reducing agents - The total change in oxidation states for the mixture is: - For `FeC2O4`: 3 units - For `FeSO4`: 1 unit - Therefore, the total change in oxidation states for the mixture is: \[ 3 + 1 = 4 \text{ units} \] ### Step 5: Set up the equation for moles of `KMnO4` - Let \( x \) be the moles of `KMnO4` required. The total equivalents of `KMnO4` must equal the total equivalents of the reducing agents: \[ 5x = 4 \text{ (total change in oxidation states)} \] - Solving for \( x \): \[ x = \frac{4}{5} \] ### Conclusion Thus, the number of moles of `KMnO4` needed to oxidize the mixture of 1 mole of `FeSO4` and 1 mole of `FeC2O4` in acidic medium is: \[ \boxed{\frac{4}{5}} \]

To solve the problem of how many moles of `KMnO4` are needed to oxidize a mixture of 1 mole of `FeSO4` and 1 mole of `FeC2O4` in acidic medium, we can follow these steps: ### Step 1: Identify the oxidation states and changes - In `KMnO4`, manganese (Mn) is in the +7 oxidation state and gets reduced to +2 in acidic medium. - The change in oxidation state for Mn is: \[ +7 \text{ (Mn in KMnO4)} \rightarrow +2 \text{ (Mn}^{2+}\text{)} \] ...
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