Comcetrated `HNO_(3)` is `63%` `HNO_(3)` by mass and has a density of `1.4g//mL`. How many millitres of this solution are requried to prepare 250 mL of a `1.20 M HNO_(3)` solution ?

Options

A. `18.0`
B. `21.42`
C. `20.0`
D. `14.21`

Answer

2

Explanation

`m=` moles of `HNO_(3)` required `=250xx1.2=300`
`100g` solution contain 1 mole `HNO_(3)`
`(100)/(1.4)mL` solution contain 1 mole `HNO_(3)`
`:." " ` molality of `HNO_(3)` solution `=(1000)/(100)xx1.40=14`
`:." "14xxV=300" "or " "V=21.42mL`.