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PCl(5) is 10% dissociated at 1 atm. What...

`PCl_(5)` is 10% dissociated at 1 atm. What is % dissociation at 4 atm .` PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)`

A

`40%`

B

`2.5%`

C

`5%`

D

`10%`

Text Solution

Verified by Experts

The correct Answer is:
3
`{:(PCl_(5)(g),hArr,PCl_(3)(g),+,Cl_(2)(g)),(P_(1),,-,,-),(P_(1)(1-alpha),,P_(1)alpha,,P_(1)alpha),(0.9P_(1),,0.1P_(1),,0.1P_(1)):}`
`K_(p)=((0.1P_(1))^(2))/(0.9P_(1))=(P_(1))/(90)`
`P_(1)=(1)/(1.1)`
So, `K_(p)=(1)/(99)`
For new condition,
`{:(PCl_(5)(g),hArr,PCl_(2)(g),+,Cl_(2)(g)),(P_(2),,-,,-),(P_(2)(1-alpha),,P_(2)alpha,,P_(2)alpha):}`
`rArrP_(2)(1+alpha)=4`
`K_(p)=(P_(2)alpha^(2))/(1-alpha)=(1)/(99)`
`alpha^(2)=(1)/(397)" "rArr" "alpha=0.05`
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