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At 87^(@)C , the following equilibrium i...

At `87^(@)`C , the following equilibrium is established .
`H_(2)(g)+S(s)hArrH_(2)s(g), K_(c)=0.08`
If 0.3 mole hydrogen and 2 mole sulphur are heated to `87^(@)C` in a 2 L vessel, what will be the concentration of `H_(2)S` at equilibrium ?

A

`0.011 M`

B

`0.022M`

C

`0.044M`

D

`0.08M`

Text Solution

Verified by Experts

The correct Answer is:
1
`K_(c)=([H_(2)S(g)])/([H_(2)(g)])" "rArr" "8xx10^(-3)=(x)/(0.3-x)" "rArr" "x=0.022`
`[H_(2)S(g)]=(0.022)/(2)=0.011M`
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