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At 27^(@)C and 1 atm pressure ,N(2)O(4) ...

At `27^(@)C` and 1 atm pressure ,`N_(2)O_(4)` is 20% dissociation into `NO_(@)` .What is the density of equilibrium mixture of `N_(2)O_(4) and NO_(2)` at `27^(@)C` and 1 atm?

A

`3.11 g//` litre

B

`2.11g//` litre

C

`4.5g//` litre

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
1
`alpha=(M_(T)-M_(O))/((n-1)M_(O))" "rArr" "0.2=(92-M_(O))/(M_(O))" "rArr" "M_(O)=76.66`
`d_("mixture")=(PM_("mixture"))/(RT)=(1xx76.66)/(0.821xx300)=3.11g//litre`
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