What will be the `pH` and `% alpha` ( degree of hydrolysis ) respectively for the salt `BA` of `0.1M` concentration ? Given `: K_(a)` for `HA=10^(-6)` and `K_(b)` for `BOH=10^(-6)`
(a)`5,1%`
(b)`7, 10%`
(c)`9, 0.01%`
(d)`7, 0.01%`

Options

A. `5,1%`
B. `7,10%`
C. `9,0.01%`
D. `7,0.01%`

Answer

2

Explanation

`:'pH=(1)/(2)pK_(w)+(1)/(2)pK_(a)-(1)/(2)pK_(b)=7" "and " "alpha=sqrt((K_(w))/(K_(a)K_(b)))=sqrt((10^(-14))/(10^(-12)))=0.1," "or % alpha=10`