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In the isothermal reversible compression...

In the isothermal reversible compression of `52.0m` mol of a perfect gas at `260 K`, the volume of the gas is reduced to one`-`third of its initial value. Calculate `w` of this process.

A

0

B

`+123J`

C

`-123J`

D

`+246J`

Text Solution

Verified by Experts

The correct Answer is:
2
`x=-nRT ln(V_(f))/(V_(l)),V_(f)=1//3V`
`nRT=(-52.0xx10^(-3)mol)xx(8.314JK^(-1)mol^(-1))xx(260K)=1.12bar(4)xx10^(2)J`
`w=(1.12bar(4)xx10^(2)J)xxln.(1)/(3)=+123J`
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