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A system absorbs 300 cal. Of heat, its v...

A system absorbs 300 cal. Of heat, its volume doubles and temperature rises from 273 to 298 K, the work done on the surrounding is 200 cal `DeltaE`, for the above reaction is

A

`100 cal`

B

`500 cal`

C

`-500 cal`

D

`-100 cal`

Text Solution

Verified by Experts

The correct Answer is:
1
`DeltaE=q+w=300+(-200)=100cal.`
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