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A 10g piece of iron ( C =0.45 J//g^(@)C ...

A `10g` piece of iron `( C =0.45 J//g^(@)C )` at `100^(@)C` is dropped into `25g` of water `( C =4.2 J//g^(@)C)` at `27^(@)C`. Find temperature of the iron and water system at thermal equilibrium .

A

`30^(@)C`

B

`33^(@)C`

C

`40^(@)C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
1
Heat lost by iron `+` Heat gained by water `=0`
`10xx0.45(T-373)+25xx4.2xx(T-300)=0`
`T=303K` or `30^(@)C`
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