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Calculate the final temperature of a mon...

Calculate the final temperature of a monoatomic ideal gas that is compressed reversible and adiabatically from `16L` to `2L` at `300 K :`

A

`600 K`

B

`1044.6 K`

C

`1200 K`

D

`2400 K`

Text Solution

Verified by Experts

The correct Answer is:
3
`TV^(gamma-1)=` constant
`:." "(T_(2))/(T_(1))=((V_(1))/(V_(2)))^(gamma-1)" "rArr" "T_(2)=300xx((16)/(2))^((5)/(3)-1)=1200K`
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