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NH(3)(g) + 3Cl(2)(g) rarr NCl(3)(g) + 3H...

`NH_(3)(g) + 3Cl_(2)(g) rarr NCl_(3)(g) + 3HCl(g), " "DeltaH_(1)`
`N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g), " "Delta H_(2)`
`H_(2)(g) + Cl_(2)(g) rarr 2HCl(g), " "Delta H_(3)`
The heat of formation of NCl3(g) in the terms of `DeltaH_(1), DeltaH_2 and DeltaH_(3)` is :

A

`DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

B

`DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

C

`DeltaH_(f)=DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`

D

None

Text Solution

Verified by Experts

The correct Answer is:
1
`(1)/(2)N_(2)(g)+(3)/(2)Cl_(2)(g)rarr NCl_(3)(g)`
`DeltaH=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(2)`
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