In a reaction `A rarr` produce, when from `8.0xx10^(-2)` M of A, half life is found to be 120 minute. For the initial concentraton `4.0xx10^(-2)M`, the half life of the reaction become 240 minute. The order of the reaction is :

Options

A. zero
B. one
C. two
D. `0.5`

Answer

3

Explanation

`((t_(1//2))_(1))/((t_(1//2))_(2))=((a_(2))/a_(1))^(n-1),(120)/(240)=((4xx10^(-2))/(8xx10^(-2)))^(n-1),n=2`