Fe is reacted with `1.0M HCI.E^(@)` for `Fe//Fe^(2+) = +0.34` volt. The correct observation (s) regarding this reaction is/are:

Options

A. `Fe` will not oxidised to `Fe^(2+)`
B. `Fe^(2+)` will be reduced to `Fe`
C. since `e.m.f.` is positive , the half cell reaction shall occur
D. since `e.m.f.` is positive, the half cell reaction shall not occur

Answer

To solve the problem, we need to analyze the reaction between iron (Fe) and hydrochloric acid (HCl) in terms of electrochemistry, specifically using the standard electrode potentials.

### Step-by-Step Solution:

1. **Identify the Half-Reactions**:
- The half-reaction for the oxidation of iron (Fe) to iron(II) ions (Fe²⁺) is:
\[ \text{Fe} \rightarrow \text{Fe}^{2+} + 2e^- \]
- The half-reaction for the reduction of hydrogen ions (from HCl) to hydrogen gas (H₂) is:
\[ 2\text{H}^+ + 2e^- \rightarrow \text{H}_2 \]

2. **Standard Electrode Potentials**:
- The standard oxidation potential for the reaction \( \text{Fe} \rightarrow \text{Fe}^{2+} \) is given as \( E^\circ = +0.34 \) V.
- The standard reduction potential for hydrogen ions is taken as \( E^\circ = 0 \) V.

3. **Determine the Cell Potential**:
- The overall cell potential (\( E^\circ_{\text{cell}} \)) can be calculated using the formula:
\[ E^\circ_{\text{cell}} = E^\circ_{\text{oxidation}} + E^\circ_{\text{reduction}} \]
- Here, the oxidation potential of Fe is \( +0.34 \) V and the reduction potential of hydrogen is \( 0 \) V:
\[ E^\circ_{\text{cell}} = (+0.34 \, \text{V}) + (0 \, \text{V}) = +0.34 \, \text{V} \]

4. **Spontaneity of the Reaction**:
- A positive cell potential indicates that the reaction is spontaneous. The Gibbs free energy change (\( \Delta G^\circ \)) for the reaction can be determined using the relationship:
\[ \Delta G^\circ = -nFE^\circ_{\text{cell}} \]
- Since \( E^\circ_{\text{cell}} \) is positive, \( \Delta G^\circ \) will be negative, confirming that the reaction is spontaneous.

5. **Conclusion**:
- From the analysis, we conclude that:
- Iron (Fe) will oxidize to Fe²⁺.
- The reaction will occur because the standard cell potential is positive.

### Observations:
- **Correct Observations**:
- Fe will oxidize to Fe²⁺.
- Since the EMF is positive, the half-cell reaction shall occur.