Equivalent conductivity of `Fe_2(SO_4)_3` is related ot molar conductivity by the expression:

Options

A. `Lambda_(eq)=Lambda_(m)`
B. `Lambda_(eq)=lambda_(m)//3`
C. `Lambda_(eq)=3Lambda_(m)`
D. `Lambda_(eq)=Lambda_(m)//6`

Answer

4

Explanation

`Lambda_(m)=n.Lambda_(eq.),` where`n=` total cationic `//` Anionic charge
`:'" "n=6:.lambda_(eq)=lambda_(m)//6`