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The equilibrium Cu^(. .)(aq)+Cu(s) hArr...

The equilibrium `Cu^(. .)(aq)+Cu(s) hArr2Cu^(.)` established at `20^(@)C` corresponds to `([Cu^(. .)])/([Cu^(+)])=2.02xx10^(4+)`. The standard potential . `E_(Cu^(. . ).Cu)^(0)=0.33` volt at this temperature . What is the standard potential `E_(Cu//Cu^(+))^(0)`?

A

`-0.457 V`

B

`-0.125V`

C

`-0.66V`

D

`-0.250V`

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The correct Answer is:
To find the standard potential \( E^\circ_{Cu/C^+} \) for the half-reaction \( Cu^+ + e^- \leftrightarrow Cu \), we can follow these steps: ### Step 1: Understand the given equilibrium expression The equilibrium established is: \[ Cu^{2+}(aq) + Cu(s) \rightleftharpoons 2Cu^{+}(aq) \] The equilibrium constant \( K \) is given by: \[ K = \frac{[Cu^{+}]^2}{[Cu^{2+}]} \] At equilibrium, this is equal to \( 2.02 \times 10^4 \). ### Step 2: Use the Nernst equation At equilibrium, the cell potential \( E_{cell} \) is 0. Therefore, we can use the Nernst equation: \[ E_{cell} = E^\circ_{cell} - \frac{0.0591}{n} \log K \] Since \( E_{cell} = 0 \), we have: \[ 0 = E^\circ_{cell} - \frac{0.0591}{n} \log K \] Thus, \[ E^\circ_{cell} = \frac{0.0591}{n} \log K \] ### Step 3: Determine \( n \) In the half-reaction \( Cu^{2+} + 2e^- \leftrightarrow 2Cu^{+} \), the transfer of electrons \( n \) is 2. ### Step 4: Calculate \( E^\circ_{cell} \) Substituting \( n = 2 \) and \( K = 2.02 \times 10^4 \): \[ E^\circ_{cell} = \frac{0.0591}{2} \log(2.02 \times 10^4) \] Calculating \( \log(2.02 \times 10^4) \): \[ \log(2.02 \times 10^4) = \log(2.02) + \log(10^4) = 0.305 + 4 = 4.305 \] Now substituting this value: \[ E^\circ_{cell} = \frac{0.0591}{2} \times 4.305 \approx 0.1275 \text{ volts} \] ### Step 5: Relate \( E^\circ_{cell} \) to the standard potentials We know: \[ E^\circ_{cell} = E^\circ_{Cu^{2+}/Cu^{+}} - E^\circ_{Cu^{+}/Cu} \] Given \( E^\circ_{Cu^{2+}/Cu} = 0.33 \) volts, we can rearrange: \[ E^\circ_{Cu^{+}/Cu} = E^\circ_{Cu^{2+}/Cu^{+}} - E^\circ_{cell} \] Substituting the known values: \[ E^\circ_{Cu^{+}/Cu} = 0.33 - 0.1275 \approx 0.2025 \text{ volts} \] ### Step 6: Final answer Thus, the standard potential \( E^\circ_{Cu/C^+} \) is approximately \( 0.2025 \) volts. ---

To find the standard potential \( E^\circ_{Cu/C^+} \) for the half-reaction \( Cu^+ + e^- \leftrightarrow Cu \), we can follow these steps: ### Step 1: Understand the given equilibrium expression The equilibrium established is: \[ Cu^{2+}(aq) + Cu(s) \rightleftharpoons 2Cu^{+}(aq) \] The equilibrium constant \( K \) is given by: ...
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