Home
Class 12
CHEMISTRY
The radius of the metal atom can be expr...

The radius of the metal atom can be expressed in terms of the length of a unit cell is `:`

A

it is `a//2` for simple cubic lattice

B

it is `(sqrt(3)a//4)` for b.c.c. lattice

C

it is `(a//2sqrt(2))` for F.C.C. lattice

D

All of the above

Text Solution

AI Generated Solution

The correct Answer is:
To find the radius of a metal atom in terms of the length of a unit cell for different types of crystal lattices, we can analyze each structure: Simple Cubic, Body-Centered Cubic (BCC), and Face-Centered Cubic (FCC). ### Step-by-Step Solution: 1. **Simple Cubic Lattice:** - In a simple cubic lattice, each corner of the cube has one atom. - The edge length of the unit cell is denoted as \( a \). - The atoms at the corners touch each other along the edge of the cube. - Therefore, the relationship between the radius \( r \) of the atom and the edge length \( a \) is: \[ a = r + r = 2r \] - Rearranging gives: \[ r = \frac{a}{2} \] 2. **Body-Centered Cubic (BCC) Lattice:** - In a BCC lattice, there is one atom at each corner and one atom in the center of the cube. - The body diagonal of the cube contains 4 atomic radii (from corner to corner through the center atom). - The length of the body diagonal can be expressed in terms of the edge length \( a \) as: \[ \text{Body diagonal} = \sqrt{3}a \] - Thus, we have: \[ 4r = \sqrt{3}a \] - Rearranging gives: \[ r = \frac{\sqrt{3}a}{4} \] 3. **Face-Centered Cubic (FCC) Lattice:** - In an FCC lattice, there are atoms at each corner and one atom at the center of each face. - The face diagonal of the cube contains 4 atomic radii. - The length of the face diagonal can be expressed in terms of the edge length \( a \) as: \[ \text{Face diagonal} = \sqrt{2}a \] - Thus, we have: \[ 4r = \sqrt{2}a \] - Rearranging gives: \[ r = \frac{\sqrt{2}a}{4} = \frac{a}{2\sqrt{2}} \] ### Summary of Results: - For Simple Cubic: \( r = \frac{a}{2} \) - For BCC: \( r = \frac{\sqrt{3}a}{4} \) - For FCC: \( r = \frac{a}{2\sqrt{2}} \) ### Conclusion: All three expressions for the radius \( r \) of the metal atom in terms of the unit cell length \( a \) are valid for their respective lattice types. Therefore, the correct answer is that all options are correct.
Promotional Banner

Topper's Solved these Questions

  • RANK BOOSTER

    RESONANCE ENGLISH|Exercise All Questions|1896 Videos
  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos

Similar Questions

Explore conceptually related problems

The radius of an atom of an element is 55 pm. What is the edge length of the unit cell if it is body-centred cubic?

In the body centered cubic unit cell and simple unit cell, the radius of atoms in terms of edge length (a) of the unit cell is respectively:

Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. What is the length of the edge of the unit cell ?

Aluminium crystallizes in an fcc structure. Atomic radius of the metal is 125 pm. What is the length of the side of the unit cell of the metal?

A metal crystallizes in BCC lattice. If the diameter of metal atom is 200 pm then the edge length of unit cell is

What is the radius of a metal atom if it crystallizes with body-centered lattice having a unit cell edge of 333 Pico meter?

Sodium crystallises in a body-centred cubic unit cell. (bcc) with edge length 4.29Å . What is the radius of the sodium atom ? What is the length of the body-diagonal of the unit cell?

Silver metal crysatllises with a face centred cubic lattice. The length of the unit cell is found to be 450 pm. Calulate the atomic radius.

A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is 'a' the closest approach between two atoms in metallic crystal will be

RESONANCE ENGLISH-SOLID STATE-PHYSICAL CHEMITRY (SOLID STATE)
  1. CsBr has bcc stucture with edge length 4.3 A .The shortest interionic ...

    Text Solution

    |

  2. A solid has a bcc structure. If the distance of closest approach betw...

    Text Solution

    |

  3. The radius of the metal atom can be expressed in terms of the length o...

    Text Solution

    |

  4. Fraction of the total volume occupied by atoms in a simple cube is:

    Text Solution

    |

  5. Lithium borohydride crystallizes in an orthormobic system with 4 molec...

    Text Solution

    |

  6. The crystal system of a compound with unit cell parameter,

    Text Solution

    |

  7. The most unsysmmetrical and symmeterical systems are, respectively:

    Text Solution

    |

  8. Three elements P, Q and R crystallize in a cubic solid lattice. The P ...

    Text Solution

    |

  9. In a face centred cubic arrangement of A and B atoms whose A atoms are...

    Text Solution

    |

  10. How many nearest and next nearest neighbours respectively does sodium ...

    Text Solution

    |

  11. If a metal has a bcc crystal structure, the coordination number is 8 b...

    Text Solution

    |

  12. In a ccp structure, the:

    Text Solution

    |

  13. The numbers of tetrahedral and octahedral holes in a ccp array of 100 ...

    Text Solution

    |

  14. In a face centred cubic arrangement of metallic atoms, what is the rel...

    Text Solution

    |

  15. An elements X ("At. mass=80g//mol") has fcc structure. Calculate no. o...

    Text Solution

    |

  16. The atomic radius of strontium (Sr) is 215 p m and it crystallizes wit...

    Text Solution

    |

  17. In the spinel structur, oxides ions are cubical-closet packed whereas ...

    Text Solution

    |

  18. Select the incorrect statement

    Text Solution

    |

  19. When NaCl is dopped with 10^(-5) "mole % of" SrCl(2), what is the no. ...

    Text Solution

    |

  20. The ionic radii for Na^(+) and Br^(-) ions are 1.012Å and 1.973Å respe...

    Text Solution

    |