When NaCl is dopped with `10^(-5) "mole % of" SrCl_(2)`, what is the no. of cationic vacanies?

Options

A. `10^(-5)xxN_(A)`
B. `10^(-7)xxN_(A)`
C. `2xx10^(-7)N_(A)`
D. None of these

Answer

2

Explanation

`:' "2Na^(+)` replaced by on` Sr^(2+),`
1 mole of NaCl contain `10^(-7)` mole of `Sr^(2+)`
`:. " "`no. of cationic vacancies `=10^(-7)xxN_(A)`