A complex is represented as `CoCl_(3)xNH_(3)`. Its 0.1 molal solution inwater shows `/_\T_(f) =0.558 k`.` K_(f) "For"H_(2)O` is 1.86 `" molality"^(-1)`. Assumeing 100% ionisation of camplex and co-ordination number of co is six, calculate formula of complex:

Options

A. `[Co(NH_(3))_(5)]Cl_(3)`
B. `[Co(NH_(3))_(5)Cl]Cl_(2)`
C. `[Co(NH_(3))_(4)Cl_(2)]Cl`
D. None of these

Answer

2

Explanation

`DeltaT_(f)=K_(f)xx`molality `xxi,`
`0.558=1.86xx0.1xxi,`
or `" "i=3`
Thus complex is `[CoCl.xNH_(3)].Cl_(2).` Since co- ordination number of Co is six. Thus complex is `[Co(NH_(3))_(3)Cl]Cl_(2)`