3.6 gram of oxygen of adsorbed on 1.2 g of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 273 K ?
A
`0.19Lg^(-1)`
B
`1 Lg^(-1)`
C
`2.1Lg^(-1)`
D
none of these
Text Solution
Verified by Experts
The correct Answer is:
3
Mass of `O_(2)` per gram of adsorbent `=(3.6)/(1.2)=3` No. of moles of `O_(2)` per gram of adsorbent `=(3)/(32)` Volume of `O_(2)` per gram of adsorbent `=(3)/(32)xx(0.082.273)/(1)=2.10`
A sample of 16 g charcoal was brought into contact with CH_(4) gas contained in a vessel of 1 litre at 27^(@) C . The presses of gas was found to fall from 760 to 608 torr. The density of chacoal sample is 1.6 g//m^(3) . What is the volume of the CH_(4) gas adsorbed per gram of the adsorbent at 608 torr and 27^(@)C ?
A sample of 16 g charcoal was brought into contact with CH_(4) gas contained in a vessel of 1 litre at 27^(@) C . The pressure of gas was found to fall from 760 to 608 torr. The density of chacoal sample is 1.6 g//m^(3) . What is the volume of the CH_(4) gas adsorbed per gram of the adsorbent at 608 torr and 27^(@)C ?
What is the volume of 6 g of hydrogen at 1.5 atm and 273^(@)C ?
Volume of 1.5 mole of a gas at 1 atm. pressure and 273K is
The conversion of oxygen to ozone occurs to the extent of 15% only. If mass of ozone that can be prepared from 67.2 of oxygen at 1 atm and 273K will be :
The conversion of oxygen to ozone occurs to the extent of 15% only. The mass of ozone that can be prepared from 67.2 L of oxygen at 1 atm and 273 K will be :
4 g of a metal oxide contains 1.6 g-oxygen, then equivalent mass of the metal is
What will be the molar volume of nitrogen and argon at 273.15 K and 1 atm ?
0.1 g of metal combines with 46.6 mL of oxygen at STP . The equivalent weight of metal is
600 mL of ozonised oxygen at STP were found to weigh one gram. What is the volume of ozone in the ozonised oxygen?
