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For an binary mixture of A and B with p(...

For an binary mixture of A and B with `p_(A)^(0)ltp_(B)^(0)`:
`x_(A)=` mole fraction of A in solution
`x_(B)=` mole fraction of B in solution
`y_(A)=` mole fraction of A in vapour phase
`y_(B)=` mole fraction of B in vapour phase solution

A

`x_(A)gty_(A)`

B

`y_(B)gty_(A)`

C

`y_(B)gtx_(B)`

D

`y_(A)gty_(B)`

Text Solution

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The correct Answer is:
To solve the problem regarding the binary mixture of components A and B, we need to analyze the relationships between the mole fractions in the liquid phase and the vapor phase. Here’s a step-by-step solution: ### Step 1: Define the Given Information We have: - \( P^0_A < P^0_B \) (the vapor pressure of A is less than that of B) - \( x_A \) = mole fraction of A in the liquid solution - \( x_B \) = mole fraction of B in the liquid solution - \( y_A \) = mole fraction of A in the vapor phase - \( y_B \) = mole fraction of B in the vapor phase ### Step 2: Write the Equations for Partial Pressures The partial pressure of component A in the vapor phase can be expressed as: \[ P'_A = P^0_A \cdot x_A \] Similarly, for component B: \[ P'_B = P^0_B \cdot x_B \] ### Step 3: Total Pressure in the System The total pressure \( P_n \) in the system is the sum of the partial pressures: \[ P_n = P'_A + P'_B = P^0_A \cdot x_A + P^0_B \cdot x_B \] ### Step 4: Expressing Mole Fractions in the Vapor Phase Using the definitions of mole fractions in the vapor phase: \[ y_A = \frac{P'_A}{P_n} = \frac{P^0_A \cdot x_A}{P^0_A \cdot x_A + P^0_B \cdot x_B} \] \[ y_B = \frac{P'_B}{P_n} = \frac{P^0_B \cdot x_B}{P^0_A \cdot x_A + P^0_B \cdot x_B} \] ### Step 5: Setting Up the Ratio Now, we can set up the ratio of the mole fractions: \[ \frac{y_A}{y_B} = \frac{P^0_A \cdot x_A}{P^0_B \cdot x_B} \] ### Step 6: Analyzing the Ratios Since \( P^0_A < P^0_B \), we can conclude that: \[ \frac{P^0_A}{P^0_B} < 1 \] Thus, we have: \[ \frac{y_A}{y_B} < \frac{x_A}{x_B} \] ### Step 7: Conclusion From the above relationship, we can derive that: \[ x_A > y_A \quad \text{and} \quad x_B < y_B \] This indicates that the mole fraction of A in the liquid phase is greater than that in the vapor phase, while the mole fraction of B in the liquid phase is less than that in the vapor phase. ### Final Answer The correct conclusion is that: - \( x_A > y_A \) - \( x_B < y_B \)

To solve the problem regarding the binary mixture of components A and B, we need to analyze the relationships between the mole fractions in the liquid phase and the vapor phase. Here’s a step-by-step solution: ### Step 1: Define the Given Information We have: - \( P^0_A < P^0_B \) (the vapor pressure of A is less than that of B) - \( x_A \) = mole fraction of A in the liquid solution - \( x_B \) = mole fraction of B in the liquid solution - \( y_A \) = mole fraction of A in the vapor phase ...
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