The reflecting surface of a plane mirror is vertical. A particle is projected in a vertical plane which is also perpendicular to the mirror. The initial speed of the particle is `10m//s` and the angle of projection is `60^@` from the normal of the mirror. The point of projection is at a distance 5m from the mirror. The particle moves towards the mirror. Just before the particle touches the mirror, the velocity of approach of the particle and the image is:

Explanation

To solve the problem, we need to determine the velocity of approach of the particle and its image just before the particle touches the mirror.

### Step-by-Step Solution:

1. **Identify the Components of Velocity:**
The initial velocity \( u \) of the particle is given as \( 10 \, \text{m/s} \) and the angle of projection \( \theta \) is \( 60^\circ \) from the normal of the mirror. We can resolve this initial velocity into two components:
- Horizontal component (parallel to the mirror):
\[
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