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Cosider f(x)=1-e^((1)/(x)-1) If S is th...

Cosider `f(x)=1-e^((1)/(x)-1)`
If S is the range of f(x), then S is

A

`(-infty,infty)`

B

`(-infty,1)`

C

`(-infty,1)`

D

`(-infty,1)-{(1-(1)/(e))}`

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The correct Answer is:
To find the range of the function \( f(x) = 1 - e^{\left(\frac{1}{x} - 1\right)} \), we will follow these steps: ### Step 1: Set \( f(x) = y \) We start by letting \( y = f(x) \): \[ y = 1 - e^{\left(\frac{1}{x} - 1\right)} \] ### Step 2: Rearrange the equation Rearranging the equation gives us: \[ e^{\left(\frac{1}{x} - 1\right)} = 1 - y \] ### Step 3: Take the natural logarithm Taking the natural logarithm of both sides: \[ \frac{1}{x} - 1 = \ln(1 - y) \] ### Step 4: Solve for \( \frac{1}{x} \) Rearranging gives: \[ \frac{1}{x} = \ln(1 - y) + 1 \] ### Step 5: Solve for \( x \) Now, we can solve for \( x \): \[ x = \frac{1}{\ln(1 - y) + 1} \] ### Step 6: Determine the conditions for \( y \) For \( x \) to be defined, the denominator must not be zero: \[ \ln(1 - y) + 1 \neq 0 \implies \ln(1 - y) \neq -1 \implies 1 - y \neq \frac{1}{e} \implies y \neq 1 - \frac{1}{e} \] ### Step 7: Determine the range of \( y \) Next, we need to consider the conditions under which \( \ln(1 - y) \) is defined: \[ 1 - y > 0 \implies y < 1 \] ### Step 8: Combine the conditions From the above steps, we have: - \( y < 1 \) - \( y \neq 1 - \frac{1}{e} \) ### Conclusion Thus, the range \( S \) of the function \( f(x) \) is: \[ S = (-\infty, 1) \setminus \left\{ 1 - \frac{1}{e} \right\} \] ### Final Answer The range \( S \) is: \[ S = (-\infty, 1) \text{ excluding } \left\{ 1 - \frac{1}{e} \right\} \]

To find the range of the function \( f(x) = 1 - e^{\left(\frac{1}{x} - 1\right)} \), we will follow these steps: ### Step 1: Set \( f(x) = y \) We start by letting \( y = f(x) \): \[ y = 1 - e^{\left(\frac{1}{x} - 1\right)} \] ...
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