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An ideal gas can be expended from an ini...

An ideal gas can be expended from an initial state to a certain volume through two different processes
(i) `pV^(2)=` constant and (ii) `p=KV^(2)` where K is a positive constant. Then

A

The total heat given to the gas in (i) is greater than in (ii)

B

final temperature in (i) will be greater than in (ii)

C

final temperature in (ii) will be greater than in (i)

D

the total heat given to the gas in (ii) is greater than in (i)

Text Solution

Verified by Experts

The correct Answer is:
B, D

from `PV=nRT`

As `P_(C)ltP_(B)` and `V_(C)=V_(B)=becauseT_(B)gtT_(C)`
`W_(AB)gtW_(AC),T_(B)-T_(A)gtT_(C)-T_(A)`
So by `i^(st)` law `Q=DeltaU+W`
`Q=(f)/(2)nRDeltaT+W`
`Q_(AB)gtQ_(AC)`
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