Mark out the incorrect order of nucleophilicity for given nucleophile:

Options

A. `CH_(3)^(ɵ)gtOH^(ɵ)gtNH_(2)^(ɵ)gtF^(ɵ)gtI^(ɵ)` (in DMF)
B. `I^(ɵ)gtBr^(ɵ)gtCl^(ɵ)gtF^(ɵ)` ( in `H_(2)O`)
C. `I^(ɵ)gtF^(ɵ)gtOH^(ɵ)gtNH_(2)^(ɵ)gtCH_(3)^(ɵ)` ( in DMSO)
D. `CH_(3)^(ɵ)gtNH_(2)^(ɵ)gtOH^(ɵ)gtF^(ɵ)` (in `H_(2)O)`

Explanation

To determine the incorrect order of nucleophilicity for the given nucleophiles, we will analyze the factors affecting nucleophilicity and compare the nucleophiles based on their characteristics.

### Step-by-Step Solution:

1. **Understand Nucleophilicity**:
- Nucleophilicity refers to the ability of a species to donate an electron pair to an electrophile. It is influenced by factors such as charge, electronegativity, and solvent effects.

2. **Identify the Nucleophiles**:
- The nucleophiles mentioned are F⁻, I⁻, CH₃⁻, NH₂⁻, and OH⁻.

3. **Analyze Nucleophilicity in Different Solvents**:
- **Polar Protic Solvents (e.g., H₂O)**:
- In polar protic solvents, larger ions (like I⁻) are better nucleophiles because they are less solvated compared to smaller ions (like F⁻). Thus, the order in polar protic solvents is:
- I⁻ > F⁻

- **Polar Aprotic Solvents (e.g., DMSO)**:
- In polar aprotic solvents, smaller ions (like F⁻) are better nucleophiles because they are not solvated as effectively. Thus, the order in polar aprotic solvents is:
- F⁻ > I⁻

4. **Compare Nucleophilicity of Other Nucleophiles**:
- **CH₃⁻, NH₂⁻, and OH⁻**:
- CH₃⁻ has a negative charge on carbon, which is electropositive and unstable, making it a strong nucleophile.
- NH₂⁻ is also a strong nucleophile, but less so than CH₃⁻.
- OH⁻ is less nucleophilic than both CH₃⁻ and NH₂⁻ because oxygen is more electronegative and holds onto its electrons more tightly.

5. **Determine the Correct Order**:
- The expected order of nucleophilicity based on the analysis is:
- CH₃⁻ > NH₂⁻ > OH⁻
- In polar protic solvents: I⁻ > F⁻
- In polar aprotic solvents: F⁻ > I⁻

6. **Identify Incorrect Statements**:
- If the options provided include:
- 1. CH₃⁻ > OH⁻ > NH₂⁻ (Incorrect)
- 2. I⁻ > F⁻ in polar protic (Correct)
- 3. NH₂⁻ > OH⁻ (Correct)
- 4. CH₃⁻ > NH₂⁻ > OH⁻ (Correct)
- The incorrect order is option 1.

### Conclusion:
The incorrect order of nucleophilicity is found in option 1.