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An infinity long cylinder of radius R ha...


An infinity long cylinder of radius R has an infinitely long cylindrical cavity of radius `(R)/(2)` are shown in the figure. The remaining portion has uniform volume charge density `rho`. The magnitude of electrical field at the centre of the cavity is-

A

`(rhoR)/(6epsilon_(0))`

B

`(rhoR)/(4epsilon_(0))`

C

`(rhoR)/(2epsilon_(0))`

D

`(rhoR)/(3epsilon_(0))`

Text Solution

Verified by Experts

The correct Answer is:
B
Electric field in cavity is given as `=(rhor)/(2epsilon_(0))`
where `r` is distance between the axis of cylinder cavity
so, E in cavity `=(rho(R)/(2))/(2epsilon_(0))=(rhoR)/(4epsilon_(0))`
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