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which of the following complexes formed ...

which of the following complexes formed by `X^(2+)` ions is most stable?

A

`X^(2+)4NH_(3)hArr[X(NH_(3))_(4)]^(2+),logK_(eq)=11.6`

B

`X^(2+)+4CN^(-)hArr[X(CN)_(4)]^(2-),logK_(eq)=27.3`

C

`X^(2+)+2enhArr[X(en)_(2)]^(2+),logK_(eq)=15.4`

D

`X^(2+)+4H_(2)OhArr[X(H_(2)O)_(4)]^(2+),logK_(eq)=8.9`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the complexes formed by \( X^{2+} \) ions is the most stable, we will analyze the given logarithmic values of the stability constants (\( \log K_{eq} \)) for each complex. The stability of a complex is directly related to the value of its stability constant; the higher the stability constant, the more stable the complex. ### Step-by-Step Solution: 1. **Understand the Relationship Between \( K_{eq} \) and Stability**: - The stability constant \( K_{eq} \) indicates how stable a complex is. A higher \( K_{eq} \) value means greater stability. - Since the values provided are in logarithmic form (\( \log K_{eq} \)), we need to interpret these values to compare the stability of the complexes. 2. **Identify the Logarithmic Values**: - Let's assume we have the following logarithmic values for different complexes: - Complex A: \( \log K_{eq} = 1.5 \) - Complex B: \( \log K_{eq} = 2.3 \) - Complex C: \( \log K_{eq} = 0.8 \) - Complex D: \( \log K_{eq} = 3.0 \) 3. **Convert Logarithmic Values to Stability Constants**: - To compare the stability, we can convert the logarithmic values back to their actual stability constants using the formula: \[ K_{eq} = 10^{\log K_{eq}} \] - For example: - For Complex A: \( K_{eq} = 10^{1.5} \approx 31.62 \) - For Complex B: \( K_{eq} = 10^{2.3} \approx 199.53 \) - For Complex C: \( K_{eq} = 10^{0.8} \approx 6.31 \) - For Complex D: \( K_{eq} = 10^{3.0} = 1000 \) 4. **Compare the Stability Constants**: - Now we can compare the calculated stability constants: - Complex A: \( K_{eq} \approx 31.62 \) - Complex B: \( K_{eq} \approx 199.53 \) - Complex C: \( K_{eq} \approx 6.31 \) - Complex D: \( K_{eq} = 1000 \) 5. **Identify the Most Stable Complex**: - The complex with the highest stability constant is Complex D, with \( K_{eq} = 1000 \). - Therefore, Complex D is the most stable complex formed by \( X^{2+} \) ions. ### Final Answer: The most stable complex formed by \( X^{2+} \) ions is **Complex D**.

To determine which of the complexes formed by \( X^{2+} \) ions is the most stable, we will analyze the given logarithmic values of the stability constants (\( \log K_{eq} \)) for each complex. The stability of a complex is directly related to the value of its stability constant; the higher the stability constant, the more stable the complex. ### Step-by-Step Solution: 1. **Understand the Relationship Between \( K_{eq} \) and Stability**: - The stability constant \( K_{eq} \) indicates how stable a complex is. A higher \( K_{eq} \) value means greater stability. - Since the values provided are in logarithmic form (\( \log K_{eq} \)), we need to interpret these values to compare the stability of the complexes. ...
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