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B(2)H(6)+NH(3)underset("heating")overset...

`B_(2)H_(6)+NH_(3)underset("heating")overset("slowly")toXoverset(Delta)toY`
Which of the following statement is incorrect?

A

X is ionic in nature

B

Hybridisation state of B in both cationic and anionic part of X is
same.

C

Y has planar structure.

D

Y is covalent and hybridisation state of all B is different.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of diborane (B₂H₆) with ammonia (NH₃) and the subsequent products formed, we will analyze the reaction step by step. ### Step 1: Identify the Reactants The reactants in this reaction are diborane (B₂H₆) and ammonia (NH₃). ### Step 2: Reaction Conditions The reaction occurs under slow heating. This indicates that the reaction is taking place at a low temperature initially. ### Step 3: Formation of Intermediate Product (X) When B₂H₆ reacts with NH₃ under slow heating, it forms an intermediate product. The expected product is: - **X = BH₂NH₃ (twice) + BH₄⁻** This indicates that we have a cationic part (BH₂NH₃) and an anionic part (BH₄⁻). ### Step 4: Further Heating of Product X Upon further heating (at a higher temperature), the intermediate product X decomposes to form: - **Y = B₃N₃H₆** This compound is also known as borazine, which has a structure similar to benzene. ### Step 5: Analyze the Statements Now we need to evaluate the statements provided in the question to identify the incorrect one. 1. **Statement 1**: "X is ionic in nature." - This is **correct** because X consists of a cation (BH₂NH₃) and an anion (BH₄⁻). 2. **Statement 2**: "The hybridization state of both B in both cationic and anionic part of X is the same." - This is **correct** as both boron atoms in BH₂NH₃ and BH₄⁻ are sp³ hybridized. 3. **Statement 3**: "Y is a planar structure." - This is **correct** because borazine (Y) has a planar structure similar to benzene. 4. **Statement 4**: "Y is covalent and the hybridization state of all B is different." - This is **incorrect** because all boron atoms in borazine (Y) have the same hybridization state, which is sp³. ### Conclusion The incorrect statement among the options provided is: - **"Y is covalent and the hybridization state of all B is different."**

To solve the question regarding the reaction of diborane (B₂H₆) with ammonia (NH₃) and the subsequent products formed, we will analyze the reaction step by step. ### Step 1: Identify the Reactants The reactants in this reaction are diborane (B₂H₆) and ammonia (NH₃). ### Step 2: Reaction Conditions The reaction occurs under slow heating. This indicates that the reaction is taking place at a low temperature initially. ...
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