A string is connected to block of mass `m=1.2` kg placed over rough table surface as shown in figure. Calculate minimum vertical force `F` ( in newton) requried to move the block. Pulley string are ideal and coefficient of friction between block ad table surface is `mu=(1)/(2)`. take `g=10m//s^(2)`

A block of mass 10 kg is moving on a rough surface as shown in figure. The frictional force acting on block is :-

A block of mass 6 kg is kept on rough surface as shown in figure. Find acceleration and friction force acting on the block. (Take g=10m//s^(2) )

A block of mass 10 kg is placed on the rough horizontal surface. A pulling force F is acting on the block which makes an angle theta above the horizontal. If coefficient of friction between block and surface is 4/3 then minimum value of force required to just move the block is (g = 10 m/s^2)

A block of mass 10 kg, moving with acceleration 2m//s^(2) on horizontal rough surface is shown in figure

Two block A and B of mass 50 kg and 300 kg respectively are placed as shown in figure. Coefficient of friction between all surface is (1)/(2) Then (take g = 10 m//s )

A horizontal force of 20 N is applied to a block of mass 4 kg resting on a rough horizontal table. If the block does not move on the table, how much frictional force the table is applying on the block. What can be said about the coefficient of static friction between the block and the table? Take g=10m/s^2 .

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal. Calculate the acceleration of the block. The coefficient of friction between the block and surface is 0.6. (Take g=10m//s^(2) )

Two block of masses M and m are connected to each other by a massless string and spring of force constant k as shown in the figure. The spring passes over a frictionless pulley connected rigidly to the egde of a stationary block A. The coefficient of friction between block M and plane horizontal surface of A is mu . The block M slides over the horizontal top surface of A and block m slides vertically downward with the same speed. The mass M is equal to

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal . Calculate the acceleration of the block . The coefficient of friction between the block and surface is 0*6 ( Take g = 10 m//s^(2) )

A block of mass 10 kg is placed on a horizontal surface as shown in the figure and a force F = 100 N is applied on the block as shown, in the figure. The block is at rest with respect to ground. If the contact force between block and ground is 25n (in Newton) then value of n is : (Take g = 10 m//s^(2))