If wavelength of photon is 1.1×`10 ^(−11)` m, h=6.6×`10 ^(−34)`Jsec, then momentum of photon is

Options

A. `6×10^(−23)kgms^(−1)`
B. `3×10^(−23)kgms^(−1)`
C. `8×10^(−23)kgms^(−1)`
D. `5×10^(−23)kgms^(−1)`

Explanation

To find the momentum of a photon given its wavelength, we can use the de Broglie relation. Here’s a step-by-step solution:

### Step 1: Write down the given values
- Wavelength of the photon (λ) = \(1.1 \times 10^{-11}\) m
- Planck's constant (h) = \(6.6 \times 10^{-34}\) J·s

### Step 2: Use the de Broglie relation
The de Broglie relation for the momentum (p) of a photon is given by the formula:
\[ p = \frac{h}{\lambda} \]

### Step 3: Substitute the values into the formula
Now, substitute the values of h and λ into the formula:
\[ p = \frac{6.6 \times 10^{-34} \text{ J·s}}{1.1 \times 10^{-11} \text{ m}} \]

### Step 4: Perform the calculation
Now, calculate the momentum:
\[ p = \frac{6.6}{1.1} \times \frac{10^{-34}}{10^{-11}} = 6 \times 10^{-23} \text{ kg·m/s} \]

### Step 5: State the final answer
Thus, the momentum of the photon is:
\[ p = 6 \times 10^{-23} \text{ kg·m/s} \]