If wavelength of photon is 3×`10 ^(−18)` m, h=6.6×`10 ^(−34)`Jsec, then momentum of photon is

Options

A. `1.1×10^(−20)kgms^(−1)`
B. `2.2×10^(−16)kgms^(−1)`
C. `2.2×10^(−18)kgms^(−1)`
D. `6×10^(−23)kgms^(−1)`

Explanation

To solve the problem of finding the momentum of a photon given its wavelength and Planck's constant, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Wavelength of the photon (λ) = \(3 \times 10^{-18}\) m
- Planck's constant (h) = \(6.6 \times 10^{-34}\) J·s

2. **Use the de Broglie wavelength formula:**
The relationship between the momentum (p) of a photon and its wavelength (λ) is given by the equation:
\[ p = \frac{h}{\lambda} \]

3. **Substitute the values into the equation:**
Plugging in the values of h and λ into the equation:
\[ p = \frac{6.6 \times 10^{-34} \text{ J·s}}{3 \times 10^{-18} \text{ m}} \]

4. **Perform the calculation:**
- First, calculate the division:
\[ p = \frac{6.6}{3} \times \frac{10^{-34}}{10^{-18}} = 2.2 \times 10^{-16} \text{ kg·m/s} \]

5. **Final result:**
The momentum of the photon is:
\[ p = 2.2 \times 10^{-16} \text{ kg·m/s} \]