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FeCr(2)O(4) (chromite) is converted to C...

`FeCr_(2)O_(4)` (chromite) is converted to Cr by following steps:
Chromite `overset(I)to Na_(2)CrO_(4) overset(II)tp Cr_(2)O_(3) overset(III)to Cr`

A

`0.05M`

B

`0.025M`

C

`0.10M`

D

`0.005M`

Text Solution

Verified by Experts

The correct Answer is:
1

Since `CHCl_(2)COOH` is relatively strongs acid havings more `K_(a)`
`{:(CHCl_(2)COONa,rarr,CHCl_(2)COO^(-),+,Na^(+)),(,,0.1,,0.1),(CHCl_(2)COOH,hArr,CHCl_(2)COO^(-),+,H^(+)),(0.2,,0,,0),((0.2-x),,(x+0.1),,x):}`
`:. " "K_(a)=([CHCl_(2)COO^(-)][H^(+)])/([CHCl_(2)COOH])`
or `" "5xx10^(-2)=([0.1+x][x])/([0.2-x])`
`:." "x=0.05`
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FeCr_(2)O_(4)( chromite ) is converted to Cr by following steps : Chromite overset(I)rarrNa_(2)CrO_(4)overset(II)rarrCr_(2)O_(3)overset(III)rarr Cr Reagents in I,II, and III step might be :

FeCr_(2)O_(4)( chromite ) is converted to Cr by following steps : Chromite overset(I)rarrNa_(2)CrO_(4)overset(II)rarrCr_(2)O_(3)overset(III)rarr Cr Reagents in I,II, and III step might be :

Toulene overset(K_(2)Cr_(2)O_(7))underset(H_(2)SO_(4))to Y. Here Y is

The conversion of K_(2)Cr_(2)O_(7) into Cr_(2)(SO_(4))_(3) is

K_(2)Cr_(2)O_(7) overset(Delta) to K_(2)CrO_(4)+Cr_(2)O_(3)+O_(2)uarr

K_(2)Cr_(2)O_(7) overset(Delta) to K_(2)CrO_(4)+Cr_(2)O_(3)+O_(2)uarr

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

Complete the following reaction: (NH_4)_2Cr_2O_7overset("∆")to

K_(2)Cr_(2)O_(7) is obtained in the following steps: 2FeCrO_(4)+2Na_(2)CO_(3)+OtoFe_(2)O_(3)+2Na_(2)CrO_(4)+2CO_(2) 2Na_(2)CrO_(4)+H_(2)SO_(4)toNa_(2)Cr_(2)O_(7)+H_(2)O+Na_(2)SO_(4) Na_(2)Cr_(2)O_(7)+2KCltoK_(2)Cr_(2)+2NaCl To get 0.25 " mol of " K_(2)Cr_(2)O_(7) , " mol of " 50% pure FeCrO_(4) required.

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