If wavelength of photon is 2.2×`10 ^(−17)` m, h=6.6×`10 ^(−34)`Jsec, then momentum of photon is

Options

A. `3×10^(−17)kgms^(−1)`
B. `1.1×10^(−20)kgms^(−1)`
C. `3.3×10^(−20)kgms^(−1)`
D. none of these

Explanation

To solve the problem of finding the momentum of a photon given its wavelength and Planck's constant, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Wavelength of the photon (λ) = \(2.2 \times 10^{-17}\) m
- Planck's constant (h) = \(6.6 \times 10^{-34}\) J·s

2. **Use the de Broglie relation:**
The momentum (p) of a photon can be calculated using the formula:
\[ p = \frac{h}{\lambda} \]

3. **Substitute the values into the formula:**
\[ p = \frac{6.6 \times 10^{-34} \text{ J·s}}{2.2 \times 10^{-17} \text{ m}} \]

4. **Perform the division:**
- Calculate the numerator:
\[ 6.6 \times 10^{-34} \]
- Calculate the denominator:
\[ 2.2 \times 10^{-17} \]
- Now divide:
\[ p = \frac{6.6}{2.2} \times \frac{10^{-34}}{10^{-17}} = 3 \times 10^{-17} \text{ kg·m/s} \]

5. **Final result:**
The momentum of the photon is:
\[ p = 3 \times 10^{-17} \text{ kg·m/s} \]