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The five successive ionisation energies ...

The five successive ionisation energies energies of an element `'X'` are `800, 1427, 2658, 25024` and `32824 "KJ mole"^(-1)` respectively . The valency of `'X'` is `:`

A

3

B

4

C

2

D

1

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To determine the valency of element 'X' based on the given successive ionization energies, we can follow these steps: ### Step-by-Step Solution: 1. **List the Ionization Energies**: The given ionization energies are: - IE1 = 800 kJ/mol - IE2 = 1427 kJ/mol - IE3 = 2658 kJ/mol - IE4 = 25024 kJ/mol - IE5 = 32824 kJ/mol 2. **Analyze the Changes in Ionization Energies**: Observe the differences between successive ionization energies: - Difference between IE1 and IE2: 1427 - 800 = 627 kJ/mol - Difference between IE2 and IE3: 2658 - 1427 = 1231 kJ/mol - Difference between IE3 and IE4: 25024 - 2658 = 22366 kJ/mol - Difference between IE4 and IE5: 32824 - 25024 = 7800 kJ/mol 3. **Identify the Significant Jump**: Notice that there is a significant jump in ionization energy between IE3 (2658 kJ/mol) and IE4 (25024 kJ/mol). This large increase indicates that after removing the third electron, the atom reaches a more stable electron configuration, likely resembling that of a noble gas. 4. **Determine the Number of Valence Electrons**: Since the first three ionization energies are relatively low compared to the fourth, we can conclude that the element 'X' has 3 valence electrons. The removal of these three electrons leads to a stable electron configuration. 5. **Conclude the Valency**: The valency of an element is defined as the number of electrons that an atom can lose, gain, or share to achieve a stable electron configuration. Since 'X' can lose 3 electrons to achieve stability, the valency of 'X' is 3. ### Final Answer: The valency of element 'X' is **3**. ---

To determine the valency of element 'X' based on the given successive ionization energies, we can follow these steps: ### Step-by-Step Solution: 1. **List the Ionization Energies**: The given ionization energies are: - IE1 = 800 kJ/mol - IE2 = 1427 kJ/mol ...
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