If ionisation energy of an atom is 10 eV & EA is `6.8eV` electronegativity of the species on pauling scale

Options

A. `98.9%`
B. `60.9%`
C. `32.9%`
D. `1.4%`

Explanation

To find the electronegativity of the species on the Pauling scale given the ionization energy and electron affinity, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Ionization Energy (IE) = 10 eV
- Electron Affinity (EA) = 6.8 eV

2. **Use Mulliken's Electronegativity Formula:**
- Mulliken's electronegativity (χ) is calculated using the formula:
\[ \chi = \frac{IE + EA}{2} \]

3. **Substitute the Values:**
- Substitute the given values into the formula:
\[ \chi = \frac{10 \, \text{eV} + 6.8 \, \text{eV}}{2} \]

4. **Calculate the Sum:**
- Calculate the sum of ionization energy and electron affinity:
\[ 10 + 6.8 = 16.8 \, \text{eV} \]

5. **Divide by 2:**
- Now divide the sum by 2 to find Mulliken's electronegativity:
\[ \chi = \frac{16.8}{2} = 8.4 \]

6. **Convert to Pauling Scale:**
- The relationship between Mulliken's electronegativity and Pauling's electronegativity is given by:
\[ \text{Pauling's Electronegativity} = \frac{\text{Mulliken's Electronegativity}}{2.8} \]
- Substitute Mulliken's value:
\[ \text{Pauling's Electronegativity} = \frac{8.4}{2.8} \]

7. **Perform the Division:**
- Calculate the value:
\[ \text{Pauling's Electronegativity} = 3 \]

### Final Answer:
The electronegativity of the species on the Pauling scale is **3**.

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